(v^2-3v-10)/(v^2-4v+4)

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Solution for (v^2-3v-10)/(v^2-4v+4) equation: 


D( v )

v^2-(4*v)+4 = 0

v^2-(4*v)+4 = 0

v^2-(4*v)+4 = 0

v^2-4*v+4 = 0

v^2-4*v+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

v = 4/(1*2)

v = 2 or v = 2

v in (-oo:2) U (2:+oo)

(v^2-(3*v)-10)/(v^2-(4*v)+4) = 0

(v^2-3*v-10)/(v^2-4*v+4) = 0

v^2-3*v-10 = 0

v^2-3*v-10 = 0

DELTA = (-3)^2-(-10*1*4)

DELTA = 49

DELTA > 0

v = (49^(1/2)+3)/(1*2) or v = (3-49^(1/2))/(1*2)

v = 5 or v = -2

(v+2)*(v-5) = 0

v^2-4*v+4 = 0

v^2-4*v+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

v = 4/(1*2)

v = 2 or v = 2

(v-2)^2 = 0

((v+2)*(v-5))/((v-2)^2) = 0

( v+2 )

v+2 = 0 // - 2

v = -2

( v-5 )

v-5 = 0 // + 5

v = 5

v in { -2, 5 }

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